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8c^2+10c-3=0
a = 8; b = 10; c = -3;
Δ = b2-4ac
Δ = 102-4·8·(-3)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-14}{2*8}=\frac{-24}{16} =-1+1/2 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+14}{2*8}=\frac{4}{16} =1/4 $
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